如题所述
设a/3=b/7=c/2=k,
则a=3k.b=7k,c=2k,代人，得，
(a+2b-3c)除以c
=(a+2b-3c)/c
=(3k+14k-6k)/2k
=11k/2k
=11/2
则a=3k.b=7k,c=2k,代人，得，
(a+2b-3c)除以c
=(a+2b-3c)/c
=(3k+14k-6k)/2k
=11k/2k
=11/2
温馨提示：答案为网友推荐，仅供参考
第1个回答 2013-05-04
解：
已知 a/3 = b/7 = c/2 ≠ 0
a = 3c/2, b = 7c/2
所以
(a+2b-3c)/c
=(3c/2+2*7c/2-3c)/c
=3/2+14/2-3
=11/2
已知 a/3 = b/7 = c/2 ≠ 0
a = 3c/2, b = 7c/2
所以
(a+2b-3c)/c
=(3c/2+2*7c/2-3c)/c
=3/2+14/2-3
=11/2
