要有答案和过程,急啊!跪求!!
第1个回答 2013-07-15
1, (m+2)(m2+4)(m+2)
=(m+2) (m+2) (m2+4)
=( m2+4m+4) (m2+4)
=(m2+4) (m2+4)+4m(m2+4)
=m4+8m+16+4m3+16m
2,20022-2001*2003
=(2001+1)(2003-1)-2001*2003
=2001*2003+2001+2003+1-2001*2003
=2001+2003+1
3, (x-5)(x+5)-(x+1)(x+5)
=x2-25-(x2+6x+5)
=-6x-30
4, (-a+2b的平方)-(a+2b)(2b-a)
=(2b-a) (2b-a)-(2b+a)(2b-a)
=4b2-4ab+a2-4b2+a2
=2 a2-4ab 5..(X-1/2y)�0�5-(X+Y)(X+1/4y)
=X�0�5-XY+1/4Y�0�5-X�0�5-1/4XY-XY-1/4Y�0�5
=-9/4XY
6.a的四次方-(1-a)(1+a)(1+a�0�5)
=a的四次方-(1-a�0�5)(1+a�0�5)
=a的四次方-1+a的四次方
=2a的四次方-1 7.已知x^n=2,y^n=3,求(x�0�5y)^2n的值 因为(x�0�5y)^2n = x^4n*y^2n
所以(x�0�5y)^2n = (x^n*x^n*x^n*x^n)(y^n*y^n)
(也就是分解成4个x^n乘2个y^n)
把x^n=2,y^n=3代入,
原式=(4*2)(3*2)
=48 8.试说明(5^2*3^2n+1)-(2^2*3^2n+2)是13 的倍数(5^2*3^2n+1)-(2^2*3^2n+2)
=25*3^(2n+1)-4*3*3^(2n+1)
=3^(2n+1)*(25-12)
=13*3^(2n+1)
所以(5^2*3^2n+1)-(2^2*3^2n+2)是13 的倍数9.若2x+y=0,求4x^3 +2xy(x+y)+y^3
4x^3 +2xy(x+y)+y^3
=4x^2+2x^2y+2xy^2+y^3
=4x^2(2x+y)+y^2(2x+y)
=(2x+y)(4x^2+y^2)
=0
10.若m^2 +m-1=0,求m^3 +2m^2+2008的值 m^2 +m-1=0
m^2 +m=1
m^3 +2m^2+2008
=(m^3+m^2)+m^2+2008
=m(m^2+m)+m^2+2008
=m^2+m+2008
=1+2008
=2009 11. (a-1)(1+a^2)(1+a)(1-2a)^2(2a+1)^2
=(a^2-1)(1+a^2)(1-4a^2)^2
=(a^4-1)(1-8a^2+16a^4)
=a^4-8a^6+16a^8-1+8a^2-16a^4
=16a^8-8a^6-15a^4+8a^2-1
12. (a+1)^2(a^2-2a+1)-(a-2)^2(a^+4a+4)
=(a+1)^2(a-1)^2-(a-2)^2(a+2)^2
=(a^2-1)^2-(a^2-4)^2
=(a^2-1+a^2-4)(a^2-1-a^2+4)
=(2a^2-5)*3
=6a^2-15 13.(1-1/4)(1-1/9)(1-1/16)……(1-1/100)要过程(1-1/4)=(1+1/2)(1-1/2)=3/2*1/2
(1-1/9)=(1+1/3)(1-1/3)=4/3*2/3
……
(1-1/100)=(1+1/10)(1-1/10)=11/10*9/10
(1-1/4)(1-1/9)(1-1/16)…… (1-1/81)(1-1/100)
=1/2*3/2*2/3*4/3……9/10*11/10
=11/20 14.(x-5)(x+5)-(x+1)(x+5)
=.=(x+5)(x-5-x+1)=-4x-20
15.已知a^2+4a+(a+b)^2+10(a+b)+29=0
求:3a^2-〖a^2b-(3ab-a^2b)-4a^〗-2ab的值
、(a+2)^2+(a+b+5)^2=0
∵非负的数相加等于零,只原式有可能是均为0
∴a+2=0且a+b+5=0
∴a=-2,b=-3
合并同类项,得
原式=7a^2-2a^2b+ab=58 16.x^2+mx-15=(x+3)(x+n)
x^2+mx-15=x^2+(n+3)x+3n
由对应系数相等,可得
m=n+3
-15=3n
解得m=-2,n=-5
17.4^m·8^(m+1)÷2^m的值为8192,则M的值全部化为2的指数函数
原式=2^(2m)*2^(3m+3)/2^m=2^(4m+3)
又∵8192=2^13
∴4m+3=13,
解得m=2.5 18.甲、乙两人共同计算一道整式乘法:(2x+a)(3x+b) 由于甲抄错了第一个多项式中a的符号,得到的结果为6(x的平方)+11x-10,由于乙漏抄 了第二个多项式中x的系数,得到的结果为2(X的平方)-9x+10。 (1)你能否知道式子中a、b的值各是多少? (2)请你算出这道整式乘法的正确结果. 甲:(2x-a)(3x+b)=6x^2+(2b-3a)x-ab=6x^2+11x-10
乙:(2x+a)(x+b)=2x^2+(2b+a)x+ab=2x^2-9x+10
所以:2b-3a=11
a+2b=-9
a=-5,b=-2
(2)正确的是:(2x-5)(3x-2)=6x^2-(4+15)x+10=6x^2-19x+10 19(2a+1/2b)�0�5(2a-1/2b)�0�5
=[(2a+1/2b)*(2a-1/2b)]�0�5
=[(2a)^2-(1/2b)^2]�0�5
=(4a^2-1/4b^2)�0�5
=16a^4-2a^2b^2+1/16b^4
20.6(7+1)(7�0�5+1)(7四次方+1)-(7八次方+1)+1
=(7-1)(7+1)(7�0�5+1)(7四次方+1)-(7八次方+1)+1
=(7�0�5-1)(7�0�5+1)(7四次方+1)-(7八次方+1)+1
=(7四次方-1)(7四次方+1)-(7八次方+1)+1
=7八次方-1-(7八次方+1)+1
=-1 21.(2x^2-x-1)^3=ax^6+bx^5+cx^4+dx^3+ex^2+fx+g 求a+c+e令x=1:(2-1-1)^3=0=a+b+c+d+e+f+g..........[1]
令x=0:
(0-0-1)^3=-1=g
令x=-1:(2+1-1)^3=8=a-b+c-d+e-f+g........[2]
[1]+[2]:2a+2c+2e+2g=8
a+c+e-1=4
a+c+e=5 22.899×901+1
=(900-1)*(900+1)+1
=900^2-1+1
=900^2
=810000
23.123^2-124×122
=123^2-(123+1)*(123-1)
=123^2-(123^2-1)
=123^2-123^2+1
=1 24.比较2的333次方与3的222次方的大小
2^333=8^111
3^222=9^111
所以 2^333<3^222
25. 8的N+1次方=16的N-2次方,求N的值 原方程化为
2^3n+3=2^4n-8
3n+3=4n-8
n=11本回答被网友采纳
=(m+2) (m+2) (m2+4)
=( m2+4m+4) (m2+4)
=(m2+4) (m2+4)+4m(m2+4)
=m4+8m+16+4m3+16m
2,20022-2001*2003
=(2001+1)(2003-1)-2001*2003
=2001*2003+2001+2003+1-2001*2003
=2001+2003+1
3, (x-5)(x+5)-(x+1)(x+5)
=x2-25-(x2+6x+5)
=-6x-30
4, (-a+2b的平方)-(a+2b)(2b-a)
=(2b-a) (2b-a)-(2b+a)(2b-a)
=4b2-4ab+a2-4b2+a2
=2 a2-4ab 5..(X-1/2y)�0�5-(X+Y)(X+1/4y)
=X�0�5-XY+1/4Y�0�5-X�0�5-1/4XY-XY-1/4Y�0�5
=-9/4XY
6.a的四次方-(1-a)(1+a)(1+a�0�5)
=a的四次方-(1-a�0�5)(1+a�0�5)
=a的四次方-1+a的四次方
=2a的四次方-1 7.已知x^n=2,y^n=3,求(x�0�5y)^2n的值 因为(x�0�5y)^2n = x^4n*y^2n
所以(x�0�5y)^2n = (x^n*x^n*x^n*x^n)(y^n*y^n)
(也就是分解成4个x^n乘2个y^n)
把x^n=2,y^n=3代入,
原式=(4*2)(3*2)
=48 8.试说明(5^2*3^2n+1)-(2^2*3^2n+2)是13 的倍数(5^2*3^2n+1)-(2^2*3^2n+2)
=25*3^(2n+1)-4*3*3^(2n+1)
=3^(2n+1)*(25-12)
=13*3^(2n+1)
所以(5^2*3^2n+1)-(2^2*3^2n+2)是13 的倍数9.若2x+y=0,求4x^3 +2xy(x+y)+y^3
4x^3 +2xy(x+y)+y^3
=4x^2+2x^2y+2xy^2+y^3
=4x^2(2x+y)+y^2(2x+y)
=(2x+y)(4x^2+y^2)
=0
10.若m^2 +m-1=0,求m^3 +2m^2+2008的值 m^2 +m-1=0
m^2 +m=1
m^3 +2m^2+2008
=(m^3+m^2)+m^2+2008
=m(m^2+m)+m^2+2008
=m^2+m+2008
=1+2008
=2009 11. (a-1)(1+a^2)(1+a)(1-2a)^2(2a+1)^2
=(a^2-1)(1+a^2)(1-4a^2)^2
=(a^4-1)(1-8a^2+16a^4)
=a^4-8a^6+16a^8-1+8a^2-16a^4
=16a^8-8a^6-15a^4+8a^2-1
12. (a+1)^2(a^2-2a+1)-(a-2)^2(a^+4a+4)
=(a+1)^2(a-1)^2-(a-2)^2(a+2)^2
=(a^2-1)^2-(a^2-4)^2
=(a^2-1+a^2-4)(a^2-1-a^2+4)
=(2a^2-5)*3
=6a^2-15 13.(1-1/4)(1-1/9)(1-1/16)……(1-1/100)要过程(1-1/4)=(1+1/2)(1-1/2)=3/2*1/2
(1-1/9)=(1+1/3)(1-1/3)=4/3*2/3
……
(1-1/100)=(1+1/10)(1-1/10)=11/10*9/10
(1-1/4)(1-1/9)(1-1/16)…… (1-1/81)(1-1/100)
=1/2*3/2*2/3*4/3……9/10*11/10
=11/20 14.(x-5)(x+5)-(x+1)(x+5)
=.=(x+5)(x-5-x+1)=-4x-20
15.已知a^2+4a+(a+b)^2+10(a+b)+29=0
求:3a^2-〖a^2b-(3ab-a^2b)-4a^〗-2ab的值
、(a+2)^2+(a+b+5)^2=0
∵非负的数相加等于零,只原式有可能是均为0
∴a+2=0且a+b+5=0
∴a=-2,b=-3
合并同类项,得
原式=7a^2-2a^2b+ab=58 16.x^2+mx-15=(x+3)(x+n)
x^2+mx-15=x^2+(n+3)x+3n
由对应系数相等,可得
m=n+3
-15=3n
解得m=-2,n=-5
17.4^m·8^(m+1)÷2^m的值为8192,则M的值全部化为2的指数函数
原式=2^(2m)*2^(3m+3)/2^m=2^(4m+3)
又∵8192=2^13
∴4m+3=13,
解得m=2.5 18.甲、乙两人共同计算一道整式乘法:(2x+a)(3x+b) 由于甲抄错了第一个多项式中a的符号,得到的结果为6(x的平方)+11x-10,由于乙漏抄 了第二个多项式中x的系数,得到的结果为2(X的平方)-9x+10。 (1)你能否知道式子中a、b的值各是多少? (2)请你算出这道整式乘法的正确结果. 甲:(2x-a)(3x+b)=6x^2+(2b-3a)x-ab=6x^2+11x-10
乙:(2x+a)(x+b)=2x^2+(2b+a)x+ab=2x^2-9x+10
所以:2b-3a=11
a+2b=-9
a=-5,b=-2
(2)正确的是:(2x-5)(3x-2)=6x^2-(4+15)x+10=6x^2-19x+10 19(2a+1/2b)�0�5(2a-1/2b)�0�5
=[(2a+1/2b)*(2a-1/2b)]�0�5
=[(2a)^2-(1/2b)^2]�0�5
=(4a^2-1/4b^2)�0�5
=16a^4-2a^2b^2+1/16b^4
20.6(7+1)(7�0�5+1)(7四次方+1)-(7八次方+1)+1
=(7-1)(7+1)(7�0�5+1)(7四次方+1)-(7八次方+1)+1
=(7�0�5-1)(7�0�5+1)(7四次方+1)-(7八次方+1)+1
=(7四次方-1)(7四次方+1)-(7八次方+1)+1
=7八次方-1-(7八次方+1)+1
=-1 21.(2x^2-x-1)^3=ax^6+bx^5+cx^4+dx^3+ex^2+fx+g 求a+c+e令x=1:(2-1-1)^3=0=a+b+c+d+e+f+g..........[1]
令x=0:
(0-0-1)^3=-1=g
令x=-1:(2+1-1)^3=8=a-b+c-d+e-f+g........[2]
[1]+[2]:2a+2c+2e+2g=8
a+c+e-1=4
a+c+e=5 22.899×901+1
=(900-1)*(900+1)+1
=900^2-1+1
=900^2
=810000
23.123^2-124×122
=123^2-(123+1)*(123-1)
=123^2-(123^2-1)
=123^2-123^2+1
=1 24.比较2的333次方与3的222次方的大小
2^333=8^111
3^222=9^111
所以 2^333<3^222
25. 8的N+1次方=16的N-2次方,求N的值 原方程化为
2^3n+3=2^4n-8
3n+3=4n-8
n=11本回答被网友采纳