如题所述
y=f(x)/g(x)
y'=[f'(x)g(x)-g'(x)f(x)]/g^2(x)
y'=[x'(x-1)-(x-1)'x]/(x-1)^2
y'=(x-1-x)/(x-1)^2
y'=-1/(x-1)^2
y'=[f'(x)g(x)-g'(x)f(x)]/g^2(x)
y'=[x'(x-1)-(x-1)'x]/(x-1)^2
y'=(x-1-x)/(x-1)^2
y'=-1/(x-1)^2
温馨提示:答案为网友推荐,仅供参考