如题所述
显然dx/dt=a-acost
dy/dt=asint
所以dy/dx=(a-acost)/(asint)
=(1-cost)/sint
再求导得到二阶导数
(dy/dx)/dt *dt/dx
=d[(1-cost)/sint]/dt *1/(a-acost)
=[sint *sint -(1-cost)*cost]/(sint)^2 *1/(a-acost)
=(1-cost)/(sint)^2 *1/a *1/(1-cost)
=1/a *1/(sint)^2
dy/dt=asint
所以dy/dx=(a-acost)/(asint)
=(1-cost)/sint
再求导得到二阶导数
(dy/dx)/dt *dt/dx
=d[(1-cost)/sint]/dt *1/(a-acost)
=[sint *sint -(1-cost)*cost]/(sint)^2 *1/(a-acost)
=(1-cost)/(sint)^2 *1/a *1/(1-cost)
=1/a *1/(sint)^2
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