已知a比b=c比d=e比f=3比2,则a+2k-e比b+2d-f等于多少

a:b=c:d=e:f=3:2
a=(3/2)b c=(3/2)d e=(3/2)f
则，(a+2c-e)=(3/2)b+2(3/2)d-(3/2)f=(3/2)b+3d-(3/2)f
(a+2c-e):(b+2d-f)=[(3/2)b+3d-(3/2)f]:(b+2d-f)
上式上下各乘6
则为 3(3b+6d-3f):2(3b+6d-3f)=3:2

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