需要详细的过程
ä¸è§å½¢ABF2çå¨é¿
=AF2ï¼BF2ï¼AB
=AF2ï¼BF2ï¼AF1ï¼BF1
=(AF2ï¼BF2)ï¼(AF1ï¼BF1)
=2aï¼2a
=4a
=16
=AF2ï¼BF2ï¼AB
=AF2ï¼BF2ï¼AF1ï¼BF1
=(AF2ï¼BF2)ï¼(AF1ï¼BF1)
=2aï¼2a
=4a
=16
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第1个回答 2012-09-21
三角形ABF2的周长=4a=4×4=16